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In the circuit shown in figure, initially K1 is closed and K2 is open. What are the charges on each capacitors. Then K1 was opened and K2 was closed (order is important),

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प्रश्न

In the circuit shown in figure, initially K1 is closed and K2 is open. What are the charges on each capacitors.

Then K1 was opened and K2 was closed (order is important), What will be the charge on each capacitor now? [C = 1µF]

दीर्घउत्तर
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उत्तर


Initially: `V oo 1/C` and `V_1 + V_2 = E`

⇒ `V_1 = 3V` and `V_2 = 6V`

∴ `Q_1 = C_1V_1 = 6C xx 3 = 18muC`

`Q_2 = 9muC` and `Q_3 = 0`

Later: `Q_2 = Q"'"_2 + Q_3`

With `C_2V + C_3V = Q2`

⇒ `V = Q_2/(C_2 + C_3) = (3/2)V`

`Q"'"_2 = (9/2)muC` and  `Q"'"_3 = (9/2)muC`

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अध्याय 2: Electrostatic Potential And Capacitance - MCQ I [पृष्ठ १५]

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एनसीईआरटी एक्झांप्लर Physics Exemplar [English] Class 12
अध्याय 2 Electrostatic Potential And Capacitance
MCQ I | Q 2.3 | पृष्ठ १५

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