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P the Separation Between the Plates of a Charged Parallel-plate Capacitor is Increased. Which of the Following Quantities Will Change? - Physics

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प्रश्न

The separation between the plates of a charged parallel-plate capacitor is increased. Which of the following quantities will change?
(a) Charge on the capacitor
(b) Potential difference across the capacitor
(c) Energy of the capacitor
(d) Energy density between the plates

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उत्तर

(b) Potential difference across the capacitor 
(c) Energy of the capacitor.

Because the charge always remains conserved in an isolated system, it will remain the same.

Now , 

`V = (Qd)/(∈_0A)`

Here, Q, A and d are the charge, area and distance between the plates, respectively.
Thus, as d increases, V increases.
Energy is given by `E = (qV)/2`

So , it will also increase .

Energy density u , that is , energy stored per unit volume in the electric field is given by `u = 1/2∈_0E^2`

So , u will remain constant with increase in distance between the plates .

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अध्याय 9: Capacitors - MCQ [पृष्ठ १६५]

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एचसी वर्मा Concepts of Physics Vol. 2 [English] Class 11 and 12
अध्याय 9 Capacitors
MCQ | Q 5 | पृष्ठ १६५

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