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Question
Three capacitors of capacitances 6 µF each are available. The minimum and maximum capacitances, which may be obtained are
Options
6 µF, 18 µF
3 µF, 12 µF
2 µF, 12 µF
2 µF, 18 µF
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Solution
2 µF, 18 µF
The minimum capacitance can be obtained by connecting all capacitors in series. It can be calculated as follows :
`1/C = 1/6+1/6+1/6 = 1/2`
⇒ C =2 µF
The maximum capacitance can be obtained by connecting all capacitors in parallel. It can be calculated as follows :
C = 6+6+6 = 18 µF
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