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The Velocity of a Body of Mass 10 Kg Increases from 4 M/S to 8 M/S When a Force Acts on It for 2 S.

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Question

The velocity of a body of mass 10 kg increases from 4 m/s to 8 m/s when a force acts on it for 2 s.
(a) What is the momentum before the force acts ?
(b) What is the momentum after the force acts ?
(c) What is the gain in momentum per second ?
(d) What is the value of the force ?

Short/Brief Note
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Solution

(a) Momentum = Mass × velocity
= 10 × 4
= 40 kg.m/s

(b) Momentum = Mass × velocity
= 10 × 8
= 80 kg.m/s

(c) The gain in momentum per second = Momentum Gaintime
= `(80-40)/2`
= `40/2`
= 20  `"kg.m/s"^2`
(d) Force is the rate of change of momentum or the momentum gain or lost per second.
So, force = 20 kg.ms/2 = 20 N

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Chapter 2: Force and Laws of Motion - Very Short Answers 2 [Page 75]

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Lakhmir Singh Physics (Science) [English] Class 9 ICSE
Chapter 2 Force and Laws of Motion
Very Short Answers 2 | Q 32 | Page 75

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