Advertisements
Advertisements
Question
The figure formed by joining the mid-points of the adjacent sides of a parallelogram is a
Options
rectangle
parallelogram
rhombus
square
Advertisements
Solution
It is given a parallelogram ABCD in which P,Q,R and S are the mid-points AB, BC, CDand DA respectively.
PQ, QR, RS and SP are joined.

In ΔABC, P and Q are the mid-points AB and BC respectively.
Therefore,
PQ || AC and `PQ = 1/2 AC `……(i)
Similarly, In ΔADC, R and S are the mid-points CD and AD respectively.
Therefore,
SR || AC and `PQ = 1/2 AC ` ……(ii)
From (i) and (ii), we get
PQ || SR and PQ = SR
Therefore, PQRS is a parallelogram.
Hence the correct choice is (b).
APPEARS IN
RELATED QUESTIONS
In a parallelogram ABCD, determine the sum of angles ∠C and ∠D .
ABCD is a square. AC and BD intersect at O. State the measure of ∠AOB.
In a parallelogram ABCD, if ∠D = 115°, then write the measure of ∠A.
In a parallelogram ABCD, if ∠A = (3x − 20)°, ∠B = (y + 15)°, ∠C = (x + 40)°, then find the values of xand y.
In a parallelogram ABCD, the bisector of ∠A also bisects BC at X. Find AB : AD.
We get a rhombus by joining the mid-points of the sides of a
The figure formed by joining the mid-points of the adjacent sides of a rhombus is a
ABCD is a parallelogram in which diagonal AC bisects ∠BAD. If ∠BAC = 35°, then ∠ABC =
In the given figure, ∠A = 64°, ∠ABC = 58°. If BO and CO are the bisectors of ∠ABC and ∠ACB respectively of ΔABC, find x° and y°
In the given Figure, if AB = 2, BC = 6, AE = 6, BF = 8, CE = 7, and CF = 7, compute the ratio of the area of quadrilateral ABDE to the area of ΔCDF. (Use congruent property of triangles)
