Advertisements
Advertisements
प्रश्न
The figure formed by joining the mid-points of the adjacent sides of a parallelogram is a
पर्याय
rectangle
parallelogram
rhombus
square
Advertisements
उत्तर
It is given a parallelogram ABCD in which P,Q,R and S are the mid-points AB, BC, CDand DA respectively.
PQ, QR, RS and SP are joined.
In ΔABC, P and Q are the mid-points AB and BC respectively.
Therefore,
PQ || AC and `PQ = 1/2 AC `……(i)
Similarly, In ΔADC, R and S are the mid-points CD and AD respectively.
Therefore,
SR || AC and `PQ = 1/2 AC ` ……(ii)
From (i) and (ii), we get
PQ || SR and PQ = SR
Therefore, PQRS is a parallelogram.
Hence the correct choice is (b).
APPEARS IN
संबंधित प्रश्न
In Fig., below, ABCD is a parallelogram in which ∠A = 60°. If the bisectors of ∠A and ∠B meet at P, prove that AD = DP, PC = BC and DC = 2AD.
In a parallelogram ABCD, determine the sum of angles ∠C and ∠D .
In a parallelogram ABCD, write the sum of angles A and B.
In a parallelogram ABCD, if ∠A = (3x − 20)°, ∠B = (y + 15)°, ∠C = (x + 40)°, then find the values of xand y.
PQRS is a quadrilateral, PR and QS intersect each other at O. In which of the following case, PQRS is a parallelogram?
∠P = 100°, ∠Q = 80°, ∠R = 95°
The figure formed by joining the mid-points of the adjacent sides of a rhombus is a
ABCD is a parallelogram in which diagonal AC bisects ∠BAD. If ∠BAC = 35°, then ∠ABC =
In a quadrilateral ABCD, ∠A + ∠C is 2 times ∠B + ∠D. If ∠A = 140° and ∠D = 60°, then ∠B=
In the given figure, ∠A = 64°, ∠ABC = 58°. If BO and CO are the bisectors of ∠ABC and ∠ACB respectively of ΔABC, find x° and y°
ABCD is a square, diagonals AC and BD meet at O. The number of pairs of congruent triangles with vertex O are
