Advertisements
Advertisements
प्रश्न
In a parallelogram ABCD, if `∠`B = 135°, determine the measures of its other angles .
Advertisements
उत्तर
Given `∠`B = 135°
ABCD is a parallelogram
∴`∠`A = `∠`C, `∠`B = `∠`D and `∠`A + `∠`B =180°
`∠`A + `∠`B =180°
`∠`A = 45°
⇒ `∠`A = `∠`C = 45° and `∠`B = `∠`C =135°
APPEARS IN
संबंधित प्रश्न
In Fig., below, ABCD is a parallelogram in which ∠A = 60°. If the bisectors of ∠A and ∠B meet at P, prove that AD = DP, PC = BC and DC = 2AD.
In a parallelogram ABCD, determine the sum of angles ∠C and ∠D .
The sides AB and CD of a parallelogram ABCD are bisected at E and F. Prove that EBFD is a parallelogram.
In Fig. below, AB = AC and CP || BA and AP is the bisector of exterior ∠CAD of ΔABC.
Prove that (i) ∠PAC = ∠BCA (ii) ABCP is a parallelogram
PQRS is a quadrilateral, PR and QS intersect each other at O. In which of the following case, PQRS is a parallelogram?
∠P = 100°, ∠Q = 80°, ∠R = 95°
We get a rhombus by joining the mid-points of the sides of a
The figure formed by joining the mid-points of the adjacent sides of a rhombus is a
ABCD is a parallelogram in which diagonal AC bisects ∠BAD. If ∠BAC = 35°, then ∠ABC =
In a quadrilateral ABCD, ∠A + ∠C is 2 times ∠B + ∠D. If ∠A = 140° and ∠D = 60°, then ∠B=
ABCD is a square, diagonals AC and BD meet at O. The number of pairs of congruent triangles with vertex O are
