Advertisements
Advertisements
प्रश्न
P is the mid-point of side BC of a parallelogram ABCD such that ∠BAP = ∠DAP. If AD = 10 cm, then CD =
पर्याय
5 cm
6 cm
8 cm
10 cm
Advertisements
उत्तर
Parallelogram ABCD is given such that ∠BAP = ∠DAP

We haveAD = 10cm and `BC = 1/2 BC`
We need to find the measure of side CD.
Since BC || AD and AP as transversal
∠I = ∠DAP
But it is given that
∠BAP = ∠DAP
Therefore, we get:
∠I = ∠BAP
Also, sides opposite to equal angles are equal.
Then,
AB = BP …… (I)
Also, `BP = 1/2 BC`
Substituting`BP = 1/2 BC`in (I), We get:
`AB = 1/2 BC`
It is given that AD = 10cm, this means opposite side BC = 10cm,asABCD is a parallelogram. Therefore,
`AB = 1/2 (10cm)`
AB = 5cm
Or, CD = 5cm
Hence the correct choice is (a).
APPEARS IN
संबंधित प्रश्न
In a ΔABC median AD is produced to X such that AD = DX. Prove that ABXC is a
parallelogram.
In Fig. below, AB = AC and CP || BA and AP is the bisector of exterior ∠CAD of ΔABC.
Prove that (i) ∠PAC = ∠BCA (ii) ABCP is a parallelogram

In a parallelogram ABCD, if ∠D = 115°, then write the measure of ∠A.
In a parallelogram ABCD, if ∠A = (3x − 20)°, ∠B = (y + 15)°, ∠C = (x + 40)°, then find the values of xand y.
In a parallelogram ABCD, the bisector of ∠A also bisects BC at X. Find AB : AD.
We get a rhombus by joining the mid-points of the sides of a
The figure formed by joining the mid-points of the adjacent sides of a rhombus is a
The figure formed by joining the mid-points of the adjacent sides of a parallelogram is a
In a quadrilateral ABCD, ∠A + ∠C is 2 times ∠B + ∠D. If ∠A = 140° and ∠D = 60°, then ∠B=
ABCD is a square, diagonals AC and BD meet at O. The number of pairs of congruent triangles with vertex O are
