Advertisements
Advertisements
प्रश्न
In a ΔABC median AD is produced to X such that AD = DX. Prove that ABXC is a
parallelogram.
Advertisements
उत्तर

In a quadrilateral ABXC, we have
AD = DX [ Given ]
BD = DC [ Given ]
So, diagonals AX and BC bisect each other
∴ ABXC is a parallelogram
APPEARS IN
संबंधित प्रश्न
In a parallelogram ABCD, if `∠`B = 135°, determine the measures of its other angles .
P and Q are the points of trisection of the diagonal BD of a parallelogram AB Prove that CQ is parallel to AP. Prove also that AC bisects PQ.
In a parallelogram ABCD, write the sum of angles A and B.
In a parallelogram ABCD, if ∠A = (3x − 20)°, ∠B = (y + 15)°, ∠C = (x + 40)°, then find the values of xand y.
In a parallelogram ABCD, the bisector of ∠A also bisects BC at X. Find AB : AD.
The figure formed by joining the mid-points of the adjacent sides of a parallelogram is a
ABCD is a parallelogram in which diagonal AC bisects ∠BAD. If ∠BAC = 35°, then ∠ABC =
P is the mid-point of side BC of a parallelogram ABCD such that ∠BAP = ∠DAP. If AD = 10 cm, then CD =
In a quadrilateral ABCD, ∠A + ∠C is 2 times ∠B + ∠D. If ∠A = 140° and ∠D = 60°, then ∠B=
In the given Figure, if AB = 2, BC = 6, AE = 6, BF = 8, CE = 7, and CF = 7, compute the ratio of the area of quadrilateral ABDE to the area of ΔCDF. (Use congruent property of triangles)
