Advertisements
Advertisements
प्रश्न
ABCD is a parallelogram in which diagonal AC bisects ∠BAD. If ∠BAC = 35°, then ∠ABC =
पर्याय
70°
110°
90°
120°
Advertisements
उत्तर
ABCD is a parallelogram in which AC bisects ∠A.
It is given that ∠BAC = 35°
Therefore,
∠BAD = 2(∠BAC)
∠BAD = 2(35°)
∠BAD = 70°
Since, DC || AB
Therefore,
∠BAD + ∠ABC = 180°
70° +∠ABC = 180°
∠ABC = 110°
Hence, the correct choice is (b).
APPEARS IN
संबंधित प्रश्न
In a parallelogram ABCD, determine the sum of angles ∠C and ∠D .
P and Q are the points of trisection of the diagonal BD of a parallelogram AB Prove that CQ is parallel to AP. Prove also that AC bisects PQ.
In a parallelogram ABCD, write the sum of angles A and B.
In a parallelogram ABCD, if ∠D = 115°, then write the measure of ∠A.
In a parallelogram ABCD, if ∠A = (3x − 20)°, ∠B = (y + 15)°, ∠C = (x + 40)°, then find the values of xand y.
PQRS is a quadrilateral, PR and QS intersect each other at O. In which of the following case, PQRS is a parallelogram?
∠P = 100°, ∠Q = 80°, ∠R = 95°
We get a rhombus by joining the mid-points of the sides of a
The figure formed by joining the mid-points of the adjacent sides of a rhombus is a
The figure formed by joining the mid-points of the adjacent sides of a parallelogram is a
In a quadrilateral ABCD, ∠A + ∠C is 2 times ∠B + ∠D. If ∠A = 140° and ∠D = 60°, then ∠B=
