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प्रश्न
ABCD is a parallelogram in which diagonal AC bisects ∠BAD. If ∠BAC = 35°, then ∠ABC =
पर्याय
70°
110°
90°
120°
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उत्तर
ABCD is a parallelogram in which AC bisects ∠A.
It is given that ∠BAC = 35°
Therefore,
∠BAD = 2(∠BAC)
∠BAD = 2(35°)
∠BAD = 70°
Since, DC || AB
Therefore,
∠BAD + ∠ABC = 180°
70° +∠ABC = 180°
∠ABC = 110°
Hence, the correct choice is (b).
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