Advertisements
Advertisements
Question
In a ΔABC median AD is produced to X such that AD = DX. Prove that ABXC is a
parallelogram.
Advertisements
Solution

In a quadrilateral ABXC, we have
AD = DX [ Given ]
BD = DC [ Given ]
So, diagonals AX and BC bisect each other
∴ ABXC is a parallelogram
APPEARS IN
RELATED QUESTIONS
In a parallelogram ABCD, determine the sum of angles ∠C and ∠D .
ABCD is a square. AC and BD intersect at O. State the measure of ∠AOB.
In a parallelogram ABCD, write the sum of angles A and B.
In a parallelogram ABCD, if ∠D = 115°, then write the measure of ∠A.
In a parallelogram ABCD, if ∠A = (3x − 20)°, ∠B = (y + 15)°, ∠C = (x + 40)°, then find the values of xand y.
In a parallelogram ABCD, the bisector of ∠A also bisects BC at X. Find AB : AD.
The figure formed by joining the mid-points of the adjacent sides of a rhombus is a
The figure formed by joining the mid-points of the adjacent sides of a parallelogram is a
ABCD is a parallelogram in which diagonal AC bisects ∠BAD. If ∠BAC = 35°, then ∠ABC =
In the given figure, ∠A = 64°, ∠ABC = 58°. If BO and CO are the bisectors of ∠ABC and ∠ACB respectively of ΔABC, find x° and y°
