Advertisements
Advertisements
Question
In a parallelogram ABCD, if ∠D = 115°, then write the measure of ∠A.
Advertisements
Solution
In Parallelogram ABCD , ∠A and are ∠D Adjacent angles.
We know that in a parallelogram, adjacent angles are supplementary.
\[\text { Now}, \angle A + \angle D = 180^\circ \]
\[ \Rightarrow \angle A + 115^\circ = 180^\circ\]
\[ \Rightarrow \angle A = 180^\circ - 115^\circ\]
\[ \Rightarrow \angle A = 65^\circ\]
\[\text{So, measure of } \angle\text { A is } 65^\circ .\]
APPEARS IN
RELATED QUESTIONS
ABCD is a square. AC and BD intersect at O. State the measure of ∠AOB.
The sides AB and CD of a parallelogram ABCD are bisected at E and F. Prove that EBFD is a parallelogram.
In a ΔABC median AD is produced to X such that AD = DX. Prove that ABXC is a
parallelogram.
In Fig. below, AB = AC and CP || BA and AP is the bisector of exterior ∠CAD of ΔABC.
Prove that (i) ∠PAC = ∠BCA (ii) ABCP is a parallelogram
In a parallelogram ABCD, write the sum of angles A and B.
In a parallelogram ABCD, if ∠A = (3x − 20)°, ∠B = (y + 15)°, ∠C = (x + 40)°, then find the values of xand y.
In a quadrilateral ABCD, ∠A + ∠C is 2 times ∠B + ∠D. If ∠A = 140° and ∠D = 60°, then ∠B=
In the given figure, ∠A = 64°, ∠ABC = 58°. If BO and CO are the bisectors of ∠ABC and ∠ACB respectively of ΔABC, find x° and y°
In the given Figure, if AB = 2, BC = 6, AE = 6, BF = 8, CE = 7, and CF = 7, compute the ratio of the area of quadrilateral ABDE to the area of ΔCDF. (Use congruent property of triangles)
Prove that the quadrilateral formed by the bisectors of the angles of a parallelogram is a rectangle.
