Advertisements
Advertisements
प्रश्न
In a parallelogram ABCD, if ∠D = 115°, then write the measure of ∠A.
Advertisements
उत्तर
In Parallelogram ABCD , ∠A and are ∠D Adjacent angles.
We know that in a parallelogram, adjacent angles are supplementary.
\[\text { Now}, \angle A + \angle D = 180^\circ \]
\[ \Rightarrow \angle A + 115^\circ = 180^\circ\]
\[ \Rightarrow \angle A = 180^\circ - 115^\circ\]
\[ \Rightarrow \angle A = 65^\circ\]
\[\text{So, measure of } \angle\text { A is } 65^\circ .\]
APPEARS IN
संबंधित प्रश्न
In Fig., below, ABCD is a parallelogram in which ∠A = 60°. If the bisectors of ∠A and ∠B meet at P, prove that AD = DP, PC = BC and DC = 2AD.
In a parallelogram ABCD, determine the sum of angles ∠C and ∠D .
In a parallelogram ABCD, if `∠`B = 135°, determine the measures of its other angles .
The sides AB and CD of a parallelogram ABCD are bisected at E and F. Prove that EBFD is a parallelogram.
P and Q are the points of trisection of the diagonal BD of a parallelogram AB Prove that CQ is parallel to AP. Prove also that AC bisects PQ.
In a ΔABC median AD is produced to X such that AD = DX. Prove that ABXC is a
parallelogram.
In a parallelogram ABCD, write the sum of angles A and B.
The figure formed by joining the mid-points of the adjacent sides of a parallelogram is a
In the given Figure, if AB = 2, BC = 6, AE = 6, BF = 8, CE = 7, and CF = 7, compute the ratio of the area of quadrilateral ABDE to the area of ΔCDF. (Use congruent property of triangles)
Prove that the quadrilateral formed by the bisectors of the angles of a parallelogram is a rectangle.
