Advertisements
Advertisements
Question
In a parallelogram ABCD, write the sum of angles A and B.
Advertisements
Solution
In Parallelogram ABCD, ∠A and ∠Bare adjacent angles.
Thus, AB || DC
Then, we have ∠A and ∠B as consecutive interior angles which must be supplementary.
∠A + ∠B = 180°
Hence, the sum of ∠A and ∠B is 180°.
APPEARS IN
RELATED QUESTIONS
In a parallelogram ABCD, if `∠`B = 135°, determine the measures of its other angles .
ABCD is a square. AC and BD intersect at O. State the measure of ∠AOB.
The sides AB and CD of a parallelogram ABCD are bisected at E and F. Prove that EBFD is a parallelogram.
In a ΔABC median AD is produced to X such that AD = DX. Prove that ABXC is a
parallelogram.
In a parallelogram ABCD, if ∠D = 115°, then write the measure of ∠A.
In a parallelogram ABCD, the bisector of ∠A also bisects BC at X. Find AB : AD.
The figure formed by joining the mid-points of the adjacent sides of a rhombus is a
In a quadrilateral ABCD, ∠A + ∠C is 2 times ∠B + ∠D. If ∠A = 140° and ∠D = 60°, then ∠B=
In the given figure, ∠A = 64°, ∠ABC = 58°. If BO and CO are the bisectors of ∠ABC and ∠ACB respectively of ΔABC, find x° and y°
Prove that the quadrilateral formed by the bisectors of the angles of a parallelogram is a rectangle.
