Advertisements
Advertisements
Question
In a parallelogram ABCD, if `∠`B = 135°, determine the measures of its other angles .
Advertisements
Solution
Given `∠`B = 135°
ABCD is a parallelogram
∴`∠`A = `∠`C, `∠`B = `∠`D and `∠`A + `∠`B =180°
`∠`A + `∠`B =180°
`∠`A = 45°
⇒ `∠`A = `∠`C = 45° and `∠`B = `∠`C =135°
APPEARS IN
RELATED QUESTIONS
In Fig., below, ABCD is a parallelogram in which ∠A = 60°. If the bisectors of ∠A and ∠B meet at P, prove that AD = DP, PC = BC and DC = 2AD.
ABCD is a square. AC and BD intersect at O. State the measure of ∠AOB.
In a ΔABC median AD is produced to X such that AD = DX. Prove that ABXC is a
parallelogram.
In a parallelogram ABCD, write the sum of angles A and B.
In a parallelogram ABCD, if ∠A = (3x − 20)°, ∠B = (y + 15)°, ∠C = (x + 40)°, then find the values of xand y.
PQRS is a quadrilateral, PR and QS intersect each other at O. In which of the following case, PQRS is a parallelogram?
∠P = 100°, ∠Q = 80°, ∠R = 95°
We get a rhombus by joining the mid-points of the sides of a
The figure formed by joining the mid-points of the adjacent sides of a parallelogram is a
ABCD is a parallelogram in which diagonal AC bisects ∠BAD. If ∠BAC = 35°, then ∠ABC =
Prove that the quadrilateral formed by the bisectors of the angles of a parallelogram is a rectangle.
