Advertisements
Advertisements
Question
In a parallelogram ABCD, if `∠`B = 135°, determine the measures of its other angles .
Advertisements
Solution
Given `∠`B = 135°
ABCD is a parallelogram
∴`∠`A = `∠`C, `∠`B = `∠`D and `∠`A + `∠`B =180°
`∠`A + `∠`B =180°
`∠`A = 45°
⇒ `∠`A = `∠`C = 45° and `∠`B = `∠`C =135°
APPEARS IN
RELATED QUESTIONS
P and Q are the points of trisection of the diagonal BD of a parallelogram AB Prove that CQ is parallel to AP. Prove also that AC bisects PQ.
In Fig. below, AB = AC and CP || BA and AP is the bisector of exterior ∠CAD of ΔABC.
Prove that (i) ∠PAC = ∠BCA (ii) ABCP is a parallelogram
In a parallelogram ABCD, write the sum of angles A and B.
In a parallelogram ABCD, if ∠D = 115°, then write the measure of ∠A.
In a parallelogram ABCD, if ∠A = (3x − 20)°, ∠B = (y + 15)°, ∠C = (x + 40)°, then find the values of xand y.
PQRS is a quadrilateral, PR and QS intersect each other at O. In which of the following case, PQRS is a parallelogram?
∠P = 100°, ∠Q = 80°, ∠R = 95°
We get a rhombus by joining the mid-points of the sides of a
The figure formed by joining the mid-points of the adjacent sides of a rhombus is a
ABCD is a square, diagonals AC and BD meet at O. The number of pairs of congruent triangles with vertex O are
Prove that the quadrilateral formed by the bisectors of the angles of a parallelogram is a rectangle.
