मराठी

In a δAbc, E and F Are the Mid-points of Ac and Ab Respectively. the Altitude Ap to Bc Intersects Fe at Q. Prove that Aq = Qp.

Advertisements
Advertisements

प्रश्न

In a ΔABC, E and F are the mid-points of AC and AB respectively. The altitude AP to BC
intersects FE at Q. Prove that AQ = QP.

Advertisements

उत्तर

In ΔABC

E and F are midpoints of AB and  AC

∴ EF || FE, `1/2` BC =FE                [  ∴ By mid-point theorem]

In ΔABP

F is the midpoint of AB and   FQ || BP         [ ∵ EF || BC ]

∴ Q is the midpoint of AP                     [By converse of midpoint theorem]

Hence, AQ = QP

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 13: Quadrilaterals - Exercise 13.4 [पृष्ठ ६३]

APPEARS IN

आर.डी. शर्मा Mathematics [English] Class 9
पाठ 13 Quadrilaterals
Exercise 13.4 | Q 5 | पृष्ठ ६३

व्हिडिओ ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्‍न

In below fig. ABCD is a parallelogram and E is the mid-point of side B If DE and AB when produced meet at F, prove that AF = 2AB.


In the below Fig, ABCD and PQRC are rectangles and Q is the mid-point of Prove thaT

i) DP = PC (ii) PR = `1/2` AC


In the given figure, seg PD is a median of ΔPQR. Point T is the mid point of seg PD. Produced QT intersects PR at M. Show that `"PM"/"PR" = 1/3`.

[Hint: DN || QM]


D, E, and F are the mid-points of the sides AB, BC and CA of an isosceles ΔABC in which AB = BC.

Prove that ΔDEF is also isosceles.


In ΔABC, BE and CF are medians. P is a point on BE produced such that BE = EP and Q is a point on CF produced such that CF = FQ. Prove that: QAP is a straight line.


In the given figure, ABCD is a trapezium. P and Q are the midpoints of non-parallel side AD and BC respectively. Find: DC, if AB = 20 cm and PQ = 14 cm


In ΔABC, P is the mid-point of BC. A line through P and parallel to CA meets AB at point Q, and a line through Q and parallel to BC meets median AP at point R. Prove that: BC = 4QR


Side AC of a ABC is produced to point E so that CE = `(1)/(2)"AC"`. D is the mid-point of BC and ED produced meets AB at F. Lines through D and C are drawn parallel to AB which meets AC at point P and EF at point R respectively. Prove that: 3DF = EF


The figure formed by joining the mid-points of the sides of a quadrilateral ABCD, taken in order, is a square only if, ______.


P, Q, R and S are respectively the mid-points of the sides AB, BC, CD and DA of a quadrilateral ABCD in which AC = BD. Prove that PQRS is a rhombus.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×