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Question
The diagram alongside shows the refraction of a ray of light from air to a liquid.
- Write the values of (i) angle of incidence, (ii) angle of refraction.
- Use Snell’s law to find the refractive index of liquid with respect to air.
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Solution
(a) (i) Angle of incidence is the angle which the incident ray makes with normal.
∠i = 90° - 30° = 60°
(ii) The angle that the refracted beam creates with the normal is known as the angle of refraction.
∠r = 90° - 45° = 45°
(b) liquid's refractive index in relation to air.
μ Liquid = `sin i/sin r`
= `(sin 60°)/(sin 45°)`
= `(sqrt3/2)/(1/sqrt2)`
= `sqrt3/2 xx sqrt2`
= `(sqrt3 xx sqrt2)/(sqrt2 xx sqrt2)`
= `sqrt(3/2)`
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|
S. No. |
Angle of incidence |
Angle of refraction |
Angle of emergence |
|
I |
45° |
41° |
45° |
|
II |
40° |
38° |
38° |
|
III |
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41° |
40° |
|
IV |
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45° |
41° |
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(2) II
(3) III
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