Advertisements
Advertisements
प्रश्न
The diagram alongside shows the refraction of a ray of light from air to a liquid.
- Write the values of (i) angle of incidence, (ii) angle of refraction.
- Use Snell’s law to find the refractive index of liquid with respect to air.
Advertisements
उत्तर
(a) (i) Angle of incidence is the angle which the incident ray makes with normal.
∠i = 90° - 30° = 60°
(ii) The angle that the refracted beam creates with the normal is known as the angle of refraction.
∠r = 90° - 45° = 45°
(b) liquid's refractive index in relation to air.
μ Liquid = `sin i/sin r`
= `(sin 60°)/(sin 45°)`
= `(sqrt3/2)/(1/sqrt2)`
= `sqrt3/2 xx sqrt2`
= `(sqrt3 xx sqrt2)/(sqrt2 xx sqrt2)`
= `sqrt(3/2)`
APPEARS IN
संबंधित प्रश्न
Select from the following the best set-up for tracing the path of a ray of light through a rectangular glass slab:
(A) I
(B) II
(C) III
(D) IV
How does the deviation produced by a prism depend on the refraction index of its material.
The critical angle for glass-air interface is :
Comment on the statement ‘The refractive index of glass is 3/2.’
The refractive index of air with respect to glass is defined: as gµa = sin i/sin r
If r = 90°, what is the corresponding angle i called?
In the diagram below, PQ is a ray of light incident on a rectangular glass block.
How are the angles ‘i’ and ‘e’ related to each other?
The refractive index of glass with respect to air is 1.5. What is the value of the refractive index of air with respect to glass?
Observe the figure and name the ray AB, ray CD, ray GH.
