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Question
Solve the following pair of equations:
x + y = 3.3, `0.6/(3x - 2y) = -1, 3x - 2y ≠ 0`
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Solution
Given pair of linear equation are
x + y = 3.3 ......(i)
And `0.6/(3x - 2y)` = – 1
⇒ 0.6 = – 3x + 2y
⇒ 3x – 2y = – 0.6 .....(ii)
Now, multiplying equation (i) by 2 and then adding with equation (ii), we get
⇒ 2x + 2y = 6.6
⇒ 3x – 2y = – 0.6
5x = 6
⇒ x =`6/5` = 1.2
Now, put the value of x in equation (i), we get
1.2 + y = 3.3
⇒ y = 3.3 – 1.2
⇒ y = 2.1
Hence, the required values of x and y are 1.2 and 2.1, respectively.
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