Question

Solve the following pair of equations:

`x/3 + y/4 = 4, (5x)/6 - y/4 = 4`

Answer 1

Given pair of linear equations is

`x/3 + y/4` = 4

On multiplying both sides by LCM (3, 4) = 12, we get

4x + 3y = 48  ......(i)

And `(5x)/6 - y/8` = 4

On multiplying both sides by LCM (6, 8) = 24, we get

20x – 3y = 96  ......(ii)

Now, adding equations (i) and (ii), we get

24x = 144

⇒ x = 6

Now, put the value of x in equation (i), we get

4 × 6 + 3y = 48

⇒ 3y = 48 – 24

⇒ 3y = 24

⇒ y = 8

Hence, the required values of x and y are 6 and 8, respectively.