Question

Solve the following pair of equations:

x + y = 3.3, `0.6/(3x - 2y) = -1, 3x - 2y ≠ 0`

Answer 1

Given pair of linear equation are

x + y = 3.3  ......(i)

And `0.6/(3x - 2y)` = – 1

⇒ 0.6 = – 3x + 2y

⇒ 3x – 2y = – 0.6   .....(ii)

Now, multiplying equation (i) by 2 and then adding with equation (ii), we get

⇒ 2x + 2y = 6.6

⇒ 3x – 2y = – 0.6

5x = 6

⇒ x =`6/5` = 1.2

Now, put the value of x in equation (i), we get

1.2 + y = 3.3

⇒ y = 3.3 – 1.2

⇒ y = 2.1

Hence, the required values of x and y are 1.2 and 2.1, respectively.