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Solve the Following Differential Equation:- D Y D X + Y X = X 2 - Mathematics

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Question

Solve the following differential equation:-

\[\frac{dy}{dx} + \frac{y}{x} = x^2\]

Sum
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Solution

We have,

\[\frac{dy}{dx} + \frac{y}{x} = x^2 \]

\[\Rightarrow \frac{dy}{dx} + \frac{1}{x}y = x^2 \]

\[\text{Comparing with }\frac{dy}{dx} + Py = Q,\text{ we get}\]

\[P = \frac{1}{x} \]

\[Q = x^2 \]

Now,

\[I . F . = e^{\int\frac{1}{x}dx} \]

\[ = e^{\log\left| x \right|} \]

\[ = x\]

So, the solution is given by

\[y \times I . F . = \int Q \times I . F . dx + C\]

\[ \Rightarrow yx = \int x^3 + C\]

\[ \Rightarrow xy = \frac{x^4}{4} + C\]

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Chapter 22: Differential Equations - Revision Exercise [Page 147]

APPEARS IN

RD Sharma Mathematics [English] Class 12
Chapter 22 Differential Equations
Revision Exercise | Q 66.08 | Page 147

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