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Maharashtra State BoardSSC (English Medium) 9th Standard

Ratio of two adjacent sides of a parallelogram is 3 : 4, and its perimeter is 112 cm. Find the length of its each side.

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Question

Ratio of two adjacent sides of a parallelogram is 3 : 4, and its perimeter is 112 cm. Find the length of its each side.

Sum
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Solution

Let `square`ABCD be a parallelogram.

AB : BC = 3 : 4

If AB = 3x cm

So, BC = 4x cm        ...(x is the common multiple.)

∴ CD = AB = 3x cm and AD = BC = 4x cm      ...(opposite sides of parallelogram)

Perimeter of `square`ABCD = 112 cm

∴ AB + BC + CD + AD = 112

∴ 3x + 4x + 3x + 4x = 112

∴ 14x = 112

∴ x = `112/14`

∴ x = 8

∴ CD = AB = 3x = 3 × 8 = 24 cm

∴ AD = BC = 4x = 4 × 8 = 32 cm

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Chapter 5: Quadrilaterals - Problem Set 5 [Page 74]

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Balbharati Mathematics 2 [English] Standard 9 Maharashtra State Board
Chapter 5 Quadrilaterals
Problem Set 5 | Q 4 | Page 74

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