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Question
Perimeter of a parallelogram is 150 cm. One of its sides is greater than the other side by 25 cm. Find the lengths of all sides.
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Solution
Let `square`ABCD be the parallelogram and the length of AD be x cm.
One side is greater than the other by 25 cm.
∴ AB = x + 25 cm
AD = BC = x cm
AB = DC = (x + 25) cm ...[Opposite angles of a parallelogram]
Perimeter of `square`ABCD = 150 cm ...[Given]
∴ AB + BC + DC + AD = 150
∴ (x + 25) + x + (x + 25) + x = 150
∴ 4x + 50 = 150
∴ 4x = 150 – 50
∴ 4x = 100
∴ x = `100/4`
∴ x = 25
AD = BC = x = 25 cm
AB = DC = x + 25 = 25 + 25
= 50 cm
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