Advertisements
Advertisements
Question
In the above figure both RISK and CLUE are parallelograms. Find the value of x.
Advertisements
Solution
Since RISK and CLUE are parallelograms
∴∠SKR =∠RIS = 120° [·:Opposite angles are equal]
Also, ∠ULC = ∠UEC = 70° [Opposite angles are equal]
∠RIS +∠ISK = 180° [Adjacent angles are supplementary]
∠ISK = 180° - 120° = 60°
in ΔOES, we have
70° + x + 60° = 180° [Angle sum property]
x + 130° = 180°
x = 180° - 130° = 50°.
APPEARS IN
RELATED QUESTIONS
Consider the given parallelograms. Find the values of the unknowns x, y, z.
Can a quadrilateral ABCD be a parallelogram if ∠A = 70° and ∠C = 65°?
The adjacent figure HOPE is a parallelogram. Find the angle measures x, y and z. State the properties you use to find them.
In the given figure, `square`ABCD is a parallelogram. Point E is on the ray AB such that BE = AB then prove that line ED bisects seg BC at point F.
In the given figure, G is the point of concurrence of medians of ΔDEF. Take point H on ray DG such that D-G-H and DG = GH, then prove that `square`GEHF is a parallelogram.
Construct ☐ PQRS, such that l(PQ) = 3.5 cm, l(QR) = 5.6 cm, l(RS) = 3.5 cm, m∠Q = 110°, m∠R = 70°. If it is given that ☐ PQRS is a parallelogram, which of the given information is unnecessary?
In parallelogram ABCD, ∠A = 3 times ∠B. Find all the angles of the parallelogram. In the same parallelogram, if AB = 5x – 7 and CD = 3x +1 ; find the length of CD.
Given: Parallelogram ABCD in which diagonals AC and BD intersect at M.
Prove: M is the mid-point of LN.
Iron rods a, b, c, d, e, and f are making a design in a bridge as shown in the figure. If a || b, c || d, e || f, find the marked angles between d and e
ABCD is a parallelogram. The bisector of angle A intersects CD at X and bisector of angle C intersects AB at Y. Is AXCY a parallelogram? Give reason.
