Advertisements
Advertisements
Question
ABCD is a parallelogram. The bisector of angle A intersects CD at X and bisector of angle C intersects AB at Y. Is AXCY a parallelogram? Give reason.
Advertisements
Solution
Given, ABCD is a parallelogram,
So, ∠A = ∠C ...[∵ Opposite angles of a parallelogram are equal]

∴ `(∠A)/2 = (∠C)/2` ...[Dividing both the sides by 2]
∠1 = ∠2 ...[Alternative angles]
But ∠2 = ∠3 ...[∵ AB || CD and CY is the transerval]
∴ ∠1 = ∠3
But they are pair of corresponding angles.
∴ AX || YC ...(i)
AY || XC [∵ AB || DC] ...(ii)
From equations (i) and (ii), we get
AXCY is a parallelogram.
APPEARS IN
RELATED QUESTIONS
In parallelogram PQRS, ∠Q = (4x – 5)° and ∠S = (3x + 10)°. Calculate: ∠Q and ∠R.
In parallelogram ABCD, E is the mid-point of AD and F is the mid-point of BC. Prove that BFDE is a parallelogram.
The given figure shows parallelogram ABCD. Points M and N lie in diagonal BD such that DM = BN.

Prove that:
(i) ∆DMC = ∆BNA and so CM = AN
(ii) ∆AMD = ∆CNB and so AM CN
(iii) ANCM is a parallelogram.
In the given figure, AB || EC, AB = AC and AE bisects ∠DAC. Prove that:

- ∠EAC = ∠ACB
- ABCE is a parallelogram.
Iron rods a, b, c, d, e, and f are making a design in a bridge as shown in the figure. If a || b, c || d, e || f, find the marked angles between d and e
If two adjacent angles of a parallelogram are (5x – 5)° and (10x + 35)°, then the ratio of these angles is ______.
The adjacent sides of a parallelogram are 5 cm and 9 cm. Its perimeter is ______.
All rectangles are parallelograms.
The angle between the two altitudes of a parallelogram through the vertex of an obtuse angle of the parallelogram is 45°. Find the angles of the parallelogram.
In parallelogram ABCD, the angle bisector of ∠A bisects BC. Will angle bisector of B also bisect AD? Give reason.
