Advertisements
Advertisements
Question
In parallelogram ABCD, E is the mid-point of AD and F is the mid-point of BC. Prove that BFDE is a parallelogram.
Advertisements
Solution

Given: Parallelogram ABCD in which E and F are mid-points of AD and BC respectively.
To Prove: BFDE is a Parallelogram.
Proof: E is the mid-point of AD. (Given)
DE = `1/2` AD
Also, F is mid-point of BC (Given)
BF = `1/2` BC
But AD = BC (opp. sides of parallelogram)
BF = DE
Again AD || BC
⇒ DE || BF
Now DE || BF and DE = BF
Hence BFDE is a parallelogram.
APPEARS IN
RELATED QUESTIONS
Can a quadrilateral ABCD be a parallelogram if ∠D + ∠B = 180°?
Can a quadrilateral ABCD be a parallelogram if ∠A = 70° and ∠C = 65°?
In the given figure, `square`PQRS and `square`ABCR are two parallelograms. If ∠P = 110° then find the measures of all angles of `square`ABCR.

Construct a parallelogram ABCD such that l(BC) = 7 cm, m∠ABC = 40° , l(AB) = 3 cm.
Referring the adjacent figure of a parallelogram, write the answer of questions given below.

(1) If l(WZ) = 4.5 cm then l(XY) = ?
(2) If l(YZ) = 8.2 cm then l(XW) = ?
(3) If l(OX) = 2.5 cm then l(OZ) = ?
(4) If l(WO) = 3.3 cm then l(WY) = ?
(5) If m∠WZY = 120° then m∠WXY = ? and m∠XWZ = ?
Given: Parallelogram ABCD in which diagonals AC and BD intersect at M.
Prove: M is the mid-point of LN.
In parallelogram ABCD, E is the mid-point of side AB and CE bisects angle BCD. Prove that:
- AE = AD,
- DE bisects and ∠ADC and
- Angle DEC is a right angle.
Iron rods a, b, c, d, e, and f are making a design in a bridge as shown in the figure. If a || b, c || d, e || f, find the marked angles between b and c
If opposite angles of a quadrilateral are equal, it must be a parallelogram.
Draw a rough figure of a quadrilateral that is not a parallelogram but has exactly two opposite angles of equal measure.
