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Prove That: Tan π 12 + Tan π 6 + Tan π 12 Tan π 6 = 1

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Question

Prove that:
\[\tan\frac{\pi}{12} + \tan\frac{\pi}{6} + \tan\frac{\pi}{12}\tan\frac{\pi}{6} = 1\]

Short/Brief Note
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Solution

\[ \frac{\pi}{12} = 15^\circ, \frac{\pi}{6} = 30^\circ\]

\[\text{ We know that }45^\circ = 15^\circ + 30^\circ\]

Therefore, 

\[\tan\left( 45^\circ \right) = \tan\left( 15^\circ + 30^\circ \right)\]

\[ \Rightarrow 1 = \frac{\tan15^\circ + \tan30^\circ}{1 - \tan15^\circ \tan30^\circ}\]

\[ \Rightarrow 1 - \tan15^\circ \tan30^\circ = \tan15^\circ + \tan30^\circ \]

\[ \Rightarrow 1 = \tan15^\circ + \tan30^\circ + \tan15^\circ \tan30^\circ\]

\[ \Rightarrow \tan15^\circ + \tan30^\circ + \tan15^\circ\tan30^\circ = 1\]

Hence proved .

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Chapter 7: Values of Trigonometric function at sum or difference of angles - Exercise 7.1 [Page 20]

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R.D. Sharma Mathematics [English] Class 11
Chapter 7 Values of Trigonometric function at sum or difference of angles
Exercise 7.1 | Q 17.2 | Page 20

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