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Prove the following: cos4x+cos3x+cos2xsin4x+sin3x+sin2x=cot3x - Mathematics

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Question

Prove the following:

`(cos 4x + cos 3x + cos 2x)/(sin 4x + sin 3x + sin 2x) = cot 3x`

Sum
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Solution

L H.S. = `(cos 4x + cos 3x + cos 2x)/(sin 4x + sin 3x + sin 2x)`

= `((cos4 x + cos2x)+cos 3x)/((sin4x + sin 2x) + sin 3x)`

= `(2cos ((4x + 2x)/2) cos ((4x - 2x)/2) + cos 3x)/(2sin ((4x + 2x)/2) cos ((4x - 2x)/2) + sin 3x)`

= `(2cos 3x cosx+cos3x)/(2sin 3x  cosx + sin3x)`

= `(cos3x (2cosx+ 1))/(sin3x(2cosx +1))`

= `(cos3x)/(sin3x)`

= cot 3x = R.H.S.

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Chapter 3: Trigonometric Functions - Exercise 3.3 [Page 73]

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NCERT Mathematics [English] Class 11
Chapter 3 Trigonometric Functions
Exercise 3.3 | Q 21 | Page 73

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