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The value of tan 75° - cot 75° is equal to ______.

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Question

The value of tan 75° - cot 75° is equal to ______.

Options

  • `2sqrt(3)`

  • `2 + sqrt(3)`

  • `2 - sqrt(3)`

  • 1

MCQ
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Solution

The value of tan 75° – cot 75° is equal to `bbunderline(2sqrt(3))`.

Explanation:

The given expression is tan 75° − cot 75°

= `sin75^circ/cos75^circ  - cos75^circ/sin75^circ`

= `(sin^2 75^circ - cos^2 75^circ)/cos75^circ sin75^circ`

= `(2sin^2 75^circ - cos^2 75^circ)/(2 cos75^circ sin75^circ)`

= `(-2cos150^circ)/(sin150^circ)`

= `-2cot150^circ`

= `- 2 cot (180^circ - 30^circ)`

= `2cot30^circ`

= `2sqrt3`

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Chapter 3: Trigonometric Functions - Exercise [Page 56]

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NCERT Exemplar Mathematics Exemplar [English] Class 11
Chapter 3 Trigonometric Functions
Exercise | Q 38 | Page 56

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