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Question
The following figure shows two capacitors connected in series and joined to a battery. The graph shows the variation in potential as one moves from left to right on the branch containing the capacitors.
Options
C1 > C2
C1 = C2
C1 < C2
The information is not sufficient to decide the relation between C1 and C2.
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Solution
C1 < C2
Region AB shows the potential difference across capacitor C1 and region CD shows the potential difference across capacitor C2. Now, we can see from the graph that region AB is greater than region CD. Therefore, the potential difference across capacitor C1 is greater than that across capacitor C2.
∵ Capacitance, C = `Q/V`
∴ C1 < C2 (Q remains the same in series connection.)
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