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Question
For a particle performing uniform circular motion `vecv=vecomegaxxvecr`obtain an expression for linear acceleration of the particle performing non-uniform circular motion.
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Solution
`vecv=vecomegaxxvecr`
`vec(dv)/dt=vec(domega)/dtxxvecr+vecomegaxxvec(dr)/dt`
where
`(dvecomega)/dt=vecalpha,`
`(dr)/dt=vecv`
`(dvecv)/dt=veca`
`:.veca=vecalphaxxvecr+vecomegaxxvecv`
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