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Obtain a relation for the distance travelled by an object moving with a uniform acceleration in the interval between 4th and 5th seconds.

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Question

Obtain a relation for the distance travelled by an object moving with uniform acceleration in the interval between 4th and 5th seconds.

Answer in Brief
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Solution

Let the object be moving with initial velocity u ms−1 and uniform acceleration an ms−2 

∴ The distance travelled by the moving object

in ts is, s = `"ut" + 1/2 "at"^2`

Now distance travelled in 4s,

s4 = `"u" xx 4 + 1/2 "a" xx 4^2`

= 4u + 8a

Distance travelled in 5s

s5 = `"u" xx 5 + 1/2 "a" xx 5^2`

= `5"u" + 25/2 "a"`

∴ Distance travelled in the interval between 4th and 5th second

= `(5"u" + 25/2 "a") - (4"u" + 8"a")`

= `("u" + 9/2"a")"m"`

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Chapter 8: Motion - Short Answer Questions [Page 60]

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NCERT Exemplar Science Exemplar [English] Class 9
Chapter 8 Motion
Short Answer Questions | Q 23. | Page 60

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