Advertisements
Advertisements
प्रश्न
Obtain a relation for the distance travelled by an object moving with uniform acceleration in the interval between 4th and 5th seconds.
Advertisements
उत्तर
Let the object be moving with initial velocity u ms−1 and uniform acceleration an ms−2
∴ The distance travelled by the moving object
in ts is, s = `"ut" + 1/2 "at"^2`
Now distance travelled in 4s,
s4 = `"u" xx 4 + 1/2 "a" xx 4^2`
= 4u + 8a
Distance travelled in 5s
s5 = `"u" xx 5 + 1/2 "a" xx 5^2`
= `5"u" + 25/2 "a"`
∴ Distance travelled in the interval between 4th and 5th second
= `(5"u" + 25/2 "a") - (4"u" + 8"a")`
= `("u" + 9/2"a")"m"`
APPEARS IN
संबंधित प्रश्न
If on a round trip you travel 6 km and then arrive back home :
What is your final displacement ?
What information about the motion of a body are obtained from the displacement-time graph?
How can you find the following?
Velocity from a displacement – time graph.
Define displacement.
The table below shows the distance travelled by two vehicles A and B during each second:
| Time (s) | 0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 |
| Distance travelled by A (m) | 0 | 20 | 80 | 180 | 240 | 300 | 360 | 420 |
| Distance travelled by B (m) | 0 | 10 | 40 | 90 | 160 | 250 | 360 | 490 |
Give the value of the velocity at which they are meeting
Exercise Problems.
An athlete completes one round of a circular track of diameter 200 m in 40 s. What will be the distance covered and the displacement at the end of 2 m and 20 s?
Which of the following is correct?
A scalar quantity has ______.
The displacement covered by the second hand of radius V in a clock after one revolution is ______.
Distance travelled by a freely falling body is proportional to ______.
