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प्रश्न
The following table gives the displacement of a car at different instants of time.
| Time (s) | 0 | 1 | 2 | 3 | 4 |
| Displacement (m) | 0 | 5 | 10 | 15 | 20 |
- Draw the displacement-time sketch and find the average velocity of the car.
- What will be the displacement of the car at (i) 2.5 s and (ii) 4.5 s?
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उत्तर
a.
Displacement-time graph
From the part AB of the graph,
Average velocity = `("Displacement at B - Displacement at A")/"Time taken"`
= `((30 - 20) m)/((6 - 4) s)`
= `(10/2)` m/s
= 5 m/s
(b)
- From the graph, the displacement of car at 2.5 s is 12.5 m.
- From the graph, the displacement of car at 4.5 s is 22.5 m.
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संबंधित प्रश्न
Under what conditions can a body travel a certain distance and yet its resultant displacement be zero ?
The minimum distance between the start and finish points of the motion of an object is called the ______ of the object.
What can you say about the nature of motion of a body if its displacement-time graph is A straight line parallel to the time axis?
A body at rest is made to fall from the top of a tower. Its displacement at different instants is given in the following table:
| Time (in s) | 0.1 | 0.2 | 0.3 | 0.4 | 0.5 | 0.6 |
| Displacement (in m) | 0.05 | 0.20 | 0.45 | 0.80 | 1.25 | 1.80 |
Draw a displacement-time graph and state whether the motion is uniform or non-uniform?
Figure (a) shows the velocity-time graph for the motion of a body. Use it to find the displacement of the body at t = 1 s, 2 s, 3 s and 4 s, then draw on Figure (b), the displacement-time graph for it.
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| (a) | (b) |
When brakes are applied to a bus, retardation produced is 25 cm s-2 and the bus takes 20 s to stop. Calculate -
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