Advertisements
Advertisements
प्रश्न
Figure ahead represents the displacement - time sketch of motion of two cars A and B . Find :
(i) the distance by which the car B was initially ahead of car A.
(ii) the velocities of car A and car B.
(iii) the time in which car A catches car B.
(iv) the distance from start when the car A will catch the car B.
Advertisements
उत्तर
(i) Initially, the car B was 40 km ahead of car A.
(ii) Straight line depicts that cars A and B are moving with uniform velocities.
For car A
Displacement at t = 1 h is 40 m
Velocity = Displacement /time
= (40/1) km/h
= 40 km/h-1
For car B
Displacement at t = 4 h is (120 - 40) km, i.e. 80 km
Velocity = Displacement /time
= (80/4) km/h
= 20 km/h-1
(iii) Car A catches car B in 2 hours.
(iv) After starting, car A will catch car B at 80 km.
APPEARS IN
संबंधित प्रश्न
Is displacement a scalar quantity ?
The minimum distance between the start and finish points of the motion of an object is called the ______ of the object.
Define Distance.
Can you suggest the kind of motion of a body from the following distance – time graph?
A motor car slows down from 72 kmh−1 to 36 kmh−1 over a distance of 25 m. If the brakes are applied with the same force
calculate
- total time in which car comes to rest
- distance travelled by it.
Give the name of the physical quantity that corresponds to the rate of change of displacement.
A particle moves along a circular path. How many times does it change its direction in two complete rounds?
The shortest distance between two places is ______.
Write a note on the following:
knot
The displacement covered by the second hand of radius V in a clock after one revolution is ______.
