Advertisements
Advertisements
प्रश्न
Figure ahead represents the displacement - time sketch of motion of two cars A and B . Find :
(i) the distance by which the car B was initially ahead of car A.
(ii) the velocities of car A and car B.
(iii) the time in which car A catches car B.
(iv) the distance from start when the car A will catch the car B.

Advertisements
उत्तर
(i) Initially, the car B was 40 km ahead of car A.
(ii) Straight line depicts that cars A and B are moving with uniform velocities.
For car A
Displacement at t = 1 h is 40 m
Velocity = Displacement /time
= (40/1) km/h
= 40 km/h-1
For car B
Displacement at t = 4 h is (120 - 40) km, i.e. 80 km
Velocity = Displacement /time
= (80/4) km/h
= 20 km/h-1
(iii) Car A catches car B in 2 hours.
(iv) After starting, car A will catch car B at 80 km.
APPEARS IN
संबंधित प्रश्न
A farmer moves along the boundary of a square field of side 10 m in 40 s. What will be the magnitude of displacement of the farmer at the end of 2 minutes 20 seconds?
If on a round trip you travel 6 km and then arrive back home :
What is your final displacement ?
What can you say about the nature of motion of a body if its displacement-time graph is A straight line parallel to the time axis?
Give two differences between displacement and distance.
Ashok starts from his house and travels 3 km to reach his school. On finding the school gates closed, he returns to his house. What is?
The distance traveled by Ashok.
A satellite makes a complete round along its circular orbit. What is its displacement?
The graph shows how the velocity of a scooter varies with time in 50 s.
Work out: The distance traveled in 10 s, 20 s, and 50 s.
Distinguish distance and displacement.
Slope of a velocity-time graph gives
If the displacement-time graph of a particle is parallel to the time axis, the velocity of the particle is ______.
