Advertisements
Advertisements
प्रश्न
Obtain a relation for the distance travelled by an object moving with uniform acceleration in the interval between 4th and 5th seconds.
Advertisements
उत्तर
Let the object be moving with initial velocity u ms−1 and uniform acceleration an ms−2
∴ The distance travelled by the moving object
in ts is, s = `"ut" + 1/2 "at"^2`
Now distance travelled in 4s,
s4 = `"u" xx 4 + 1/2 "a" xx 4^2`
= 4u + 8a
Distance travelled in 5s
s5 = `"u" xx 5 + 1/2 "a" xx 5^2`
= `5"u" + 25/2 "a"`
∴ Distance travelled in the interval between 4th and 5th second
= `(5"u" + 25/2 "a") - (4"u" + 8"a")`
= `("u" + 9/2"a")"m"`
APPEARS IN
संबंधित प्रश्न
An ant travels a distance of 8 cm from P to Q and then moves a distance of 6 cm at right angles to PQ. Find its resultant displacement.
In which of the following cases of motion, the distance moved and the magnitude of displacement are equal?
If the displacement of an object is proportional to the square of time, then the object is moving with :
What can you say about the nature of motion of a body if its displacement-time graph is A straight line parallel to the time axis?
Figure ahead represents the displacement - time sketch of motion of two cars A and B . Find :
(i) the distance by which the car B was initially ahead of car A.
(ii) the velocities of car A and car B.
(iii) the time in which car A catches car B.
(iv) the distance from start when the car A will catch the car B.

A car starting from rest accelerates uniformly to acquire a speed 20 km h-1 in 30 min. The distance travelled by a car in this time interval will be _____________
Can you suggest the kind of motion of a body from the following distance – time graph?

Can you suggest the kind of motion of a body from the following distance – time graph?

A particle is moving in a circular path of radius r. The displacement after half a circle would be
An ant moves from one corner of a room diagonally to the opposite corner. If the dimensions of the hall are 8m x 6m, the displacement of the ant is ______.
