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Question
जर 1 – cos2θ = `1/4`, तर θ = ?
Sum
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Solution
1 – cos2θ = `1/4` ......[दिलेले]
∴ sin2θ = `1/4` .....`[(because sin^2theta + cos^2theta = 1),(therefore 1 - cos^2theta = sin^2theta)]`
∴ sin θ = `1/2` ......[दोन्ही बाजूंचे वर्गमूळ घेऊन]
∴ θ = 30° ......`[because sin 30^circ = 1/2]`
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cosec θ.`sqrt(1 - cos^2theta) = 1` हे सिद्ध करा.
जर cos θ = `24/25`, तर sin θ = ?
`(sintheta + "cosec" theta)/sin theta` = 2 + cot2θ हे सिद्ध करा.
θ चे निरसन करा:
जर x = r cosθ आणि y = r sinθ
