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In Young’S Experiment Interference Bands Were Produced on a Screen Placed at 150 Cm from Two Slits, 0.15 Mm Apart and Illuminated by the Light of Wavelength 6500 å. Calculate the Fringe Width. - Physics

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Question

In Young’s experiment interference bands were produced on a screen placed at 150 cm from two slits, 0.15 mm apart and illuminated by the light of wavelength 6500 Å. Calculate the fringe width.

Sum
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Solution

Given:
D = 150 cm = 1.5 m,
d = 0.15 mm = 1.5 x 10-4 m,
λ = 6500  Å = 6.5 x 10-7 m

To find:
Fringe width ( X )

Formula:
X = `"λD"/"d"`

Calculation:
From formula,
X = `[6.5 xx 10^-7 xx 1.5]/[1.5 xx 10^4]`

X = 6.5 x 10-3 m

X = 6.5 mm

The fringe width is 6.5 mm

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2018-2019 (March) Set 1

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