English

In a Young’s double slit experiment, the path difference at a certain point on the screen between two interfering waves is 1/8 th of the wavelength.

Advertisements
Advertisements

Question

In a Young’s double slit experiment, the path difference at a certain point on the screen between two interfering waves is `1/8`th of the wavelength. The ratio of intensity at this point to that at the centre of a bright fringe is close to ______.

Options

  • 0.80

  • 0.74

  • 0.94

  • 0.85

MCQ
Fill in the Blanks
Advertisements

Solution

In a Young’s double slit experiment, the path difference at a certain point on the screen between two interfering waves is `1/8`th of the wavelength. The ratio of intensity at this point to that at the centre of a bright fringe is close to 0.85.

Explanation:

Δx = `λ/8`

Path difference `Δphi = (2π)/λ xx Δx  = (2π)/λ xx λ/8 = π/4`

`I = I_0 cos^2 ((Δphi)/2) = I_0 cos^2(π/8)`

`I/I_0 = cos^2(π/8)` = 0.85

shaalaa.com
  Is there an error in this question or solution?
2022-2023 (March) Sample

RELATED QUESTIONS

Write three characteristic features to distinguish between the interference fringes in Young's double slit experiment and the diffraction pattern obtained due to a narrow single slit.


If Young's double slit experiment is performed in water, _________________ .


A Young's double slit experiment is performed with white light.

(a) The central fringe will be white.

(b) There will not be a completely dark fringe.

(c) The fringe next to the central will be red.

(d) The fringe next to the central will be violet.


A Young's double slit apparatus has slits separated by 0⋅28 mm and a screen 48 cm away from the slits. The whole apparatus is immersed in water and the slits are illuminated by red light \[\left( \lambda = 700\text{ nm in vacuum} \right).\] Find the fringe-width of the pattern formed on the screen.


A double slit S1 − S2 is illuminated by a coherent light of wavelength \[\lambda.\] The slits are separated by a distance d. A plane mirror is placed in front of the double slit at a distance D1 from it and a screen ∑ is placed behind the double slit at a distance D2 from it (see the following figure). The screen ∑ receives only the light reflected by the mirror. Find the fringe-width of the interference pattern on the screen.


Draw a neat labelled diagram of Young’s Double Slit experiment. Show that `beta = (lambdaD)/d` , where the terms have their usual meanings (either for bright or dark fringe).


Write the conditions on path difference under which constructive interference occurs in Young’s double-slit experiment.


In Young's double slit experiment using light of wavelength 600 nm, the slit separation is 0.8 mm and the screen is kept 1.6 m from the plane of the slits. Calculate

  1. the fringe width
  2. the distance of (a) third minimum and (b) fifth maximum, from the central maximum.

A fringe width of 6 mm was produced for two slits separated by 1 mm apart. The screen is placed 10 m away. The wavelength of light used is 'x' nm. The value of 'x' to the nearest integer is ______.


If the monochromatic source in Young’s double slit experiment is replaced by white light, then ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×