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In a Young’s double slit experiment, the path difference at a certain point on the screen between two interfering waves is 1/8 th of the wavelength.

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प्रश्न

In a Young’s double slit experiment, the path difference at a certain point on the screen between two interfering waves is `1/8`th of the wavelength. The ratio of intensity at this point to that at the centre of a bright fringe is close to ______.

विकल्प

  • 0.80

  • 0.74

  • 0.94

  • 0.85

MCQ
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उत्तर

In a Young’s double slit experiment, the path difference at a certain point on the screen between two interfering waves is `1/8`th of the wavelength. The ratio of intensity at this point to that at the centre of a bright fringe is close to 0.85.

Explanation:

Δx = `λ/8`

Path difference `Δphi = (2π)/λ xx Δx  = (2π)/λ xx λ/8 = π/4`

`I = I_0 cos^2 ((Δphi)/2) = I_0 cos^2(π/8)`

`I/I_0 = cos^2(π/8)` = 0.85

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2022-2023 (March) Sample

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