Advertisements
Advertisements
प्रश्न
The work function for a metal surface is 4.14 eV. The threshold wavelength for this metal surface is ______.
विकल्प
4125 Å
2062.5 Å
3000 Å
6000 Å
Advertisements
उत्तर
The work function for a metal surface is 4.14 eV. The threshold wavelength for this metal surface is 3000 Å.
Explanation:
w = 4.14 eV
l0 = ?
w = `"hc"/lambda_0`
`lambda_0 = "hc"/"w"`
`lambda_0 = (12,375)/("w"("ev"))` Å
`lambda_0 = (12,375)/4.14` Å
`lambda_0 = 2,985` Å
`lambda_0 ≈ 3,000` Å
APPEARS IN
संबंधित प्रश्न
(a) Estimate the speed with which electrons emitted from a heated emitter of an evacuated tube impinge on the collector maintained at a potential difference of 500 V with respect to the emitter. Ignore the small initial speeds of the electrons. The specific charge of the electron, i.e., its e/m is given to be 1.76 × 1011 C kg−1.
(b) Use the same formula you employ in (a) to obtain electron speed for an collector potential of 10 MV. Do you see what is wrong? In what way is the formula to be modified?
Can a photon be deflected by an electric field? Or by a magnetic field?
If the frequency of light in a photoelectric experiment is doubled, the stopping potential will ______.
When the intensity of a light source in increased,
(a) the number of photons emitted by the source in unit time increases
(b) the total energy of the photons emitted per unit time increases
(c) more energetic photons are emitted
(d) faster photons are emitted
An atom absorbs a photon of wavelength 500 nm and emits another photon of wavelength 700 nm. Find the net energy absorbed by the atom in the process.
(Use h = 6.63 × 10-34J-s = 4.14 × 10-15 eV-s, c = 3 × 108 m/s and me = 9.1 × 10-31kg)
The work function of a photoelectric material is 4.0 eV. (a) What is the threshold wavelength? (b) Find the wavelength of light for which the stopping potential is 2.5 V.
(Use h = 6.63 × 10-34J-s = 4.14 × 10-15 eV-s, c = 3 × 108 m/s and me = 9.1 × 10-31kg)
Answer the following question.
Plot a graph of photocurrent versus anode potential for radiation of frequency ν and intensities I1 and I2 (I1 < I2).
Define the term: stopping potential in the photoelectric effect.
Why it is the frequency and not the intensity of the light source that determines whether the emission of photoelectrons will occur or not? Explain.
Plot a graph showing the variation of photoelectric current, as a function of anode potential for two light beams having the same frequency but different intensities I1 and I2 (I1 > I2). Mention its important features.
