मराठी

The work function for a metal surface is 4.14 eV. The threshold wavelength for this metal surface is ______.

Advertisements
Advertisements

प्रश्न

The work function for a metal surface is 4.14 eV. The threshold wavelength for this metal surface is ______.

पर्याय

  • 4125 Å

  • 2062.5 Å

  • 3000 Å

  • 6000 Å

MCQ
रिकाम्या जागा भरा
Advertisements

उत्तर

The work function for a metal surface is 4.14 eV. The threshold wavelength for this metal surface is 3000 Å.

Explanation:

w = 4.14 eV

l0 = ?

w = `"hc"/lambda_0`

`lambda_0 = "hc"/"w"`

`lambda_0 = (12,375)/("w"("ev"))` Å

`lambda_0 = (12,375)/4.14` Å

`lambda_0 = 2,985` Å

`lambda_0 ≈ 3,000` Å

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
2022-2023 (March) Sample

संबंधित प्रश्‍न

Light of intensity 10−5 W m−2 falls on a sodium photo-cell of surface area 2 cm2. Assuming that the top 5 layers of sodium absorb the incident energy, estimate time required for photoelectric emission in the wave-picture of radiation. The work function for the metal is given to be about 2 eV. What is the implication of your answer?


The threshold wavelength of a metal is λ0. Light of wavelength slightly less than λ0 is incident on an insulated plate made of this metal. It is found that photoelectrons are emitted for some time and after that the emission stops. Explain.


Light of wavelength λ falls on a metal with work-function hc/λ0. Photoelectric effect will take place only if


If the wavelength of light in an experiment on photoelectric effect is doubled,
(a) photoelectric emission will not take place
(b) photoelectric emission may or may not take place
(c) the stopping potential will increase
(d) the stopping potential will decrease


The collector plate in an experiment on photoelectric effect is kept vertically above the emitter plate. A light source is put on and a saturation photocurrent is recorded. An electric field is switched on that has a vertically downward direction.


The electric field associated with a light wave is given by `E = E_0 sin [(1.57 xx 10^7  "m"^-1)(x - ct)]`. Find the stopping potential when this light is used in an experiment on photoelectric effect with the emitter having work function 1.9 eV.

(Use h = 6.63 × 10-34J-s = 4.14 × 10-15 eV-s, c = 3 × 108 m/s and me = 9.1 × 10-31kg)


Define the term: threshold frequency


Explain how does (i) photoelectric current and (ii) kinetic energy of the photoelectrons emitted in a photocell vary if the frequency of incident radiation is doubled, but keeping the intensity same?

Show the graphical variation in the above two cases.


If photons of ultraviolet light of energy 12 eV are incident on a metal surface of work function of 4 eV, then the stopping potential (in eV) will be :


Which of the following options represents the variation of photoelectric current with property of light shown on the x-axis?






Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×