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Question
In Question 2 above, if 1 part of a red pigment requires 75 mL of base, how much red pigment should we mix with 1800 mL of base?
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Solution
Let the parts of red pigment required to mix with 1800 mL of base be x.
The given information, in the form of a table, is as follows:
| Parts of red pigment | 1 | x |
| Parts of base (in mL) | 75 | 1800 |
The parts of red pigment and the parts of the base are in direct proportion.
Therefore, we obtain
`1/75 = x/1800`
=> x = `(1 xx 1800)/75`
=> x = 24
Thus, 24 parts of red pigments should be mixed with 1800 mL of base.
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