English

In Question 2 above, if 1 part of a red pigment requires 75 mL of base, how much red pigment should we mix with 1800 mL of base? - Mathematics

Advertisements
Advertisements

Question

In Question 2 above, if 1 part of a red pigment requires 75 mL of base, how much red pigment should we mix with 1800 mL of base?

Sum
Advertisements

Solution

Let the parts of red pigment required to mix with 1800 mL of base be x.

The given information, in the form of a table, is as follows:

Parts of red pigment 1 x
Parts of base (in mL) 75 1800

The parts of red pigment and the parts of the base are in direct proportion.

Therefore, we obtain

`1/75 = x/1800`

=> x = `(1 xx 1800)/75`

=> x = 24

Thus, 24 parts of red pigments should be mixed with 1800 mL of base.

shaalaa.com
  Is there an error in this question or solution?
Chapter 11: Direct and Inverse Proportions - EXERCISE 11.1 [Page 136]

APPEARS IN

NCERT Mathematics [English] Class 8
Chapter 11 Direct and Inverse Proportions
EXERCISE 11.1 | Q 3. | Page 136

Video TutorialsVIEW ALL [1]

Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×