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A mixture of paint is prepared by mixing 1 part of red pigments with 8 parts of base. In the following table, find the parts of the base that need to be added. Parts of red pigment 1 4 7 12 20 - Mathematics

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Question

A mixture of paint is prepared by mixing 1 part of red pigments with 8 parts of base. In the following table, find the parts of the base that need to be added.

Parts of red pigment 1 4 7 12 20
parts of base 8 .... .... .... ....
Sum
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Solution

The given mixture of paint is prepared by mixing 1 part of red pigments with 8 parts of base. For more parts of red pigments, the parts of the base will also be more.

Therefore, the parts of red pigments and the parts of the base are in direct proportion. The given information, in the form of a table, is as follows.

According to direct proportion,

`x_1/4 = 8/1`

=> x1 = 4 × 8

= 32

`x_2/7 = 8/1`

=> x2 = 7 × 8

= 56

`x_3/12 = 8/1`

=> x3 = 8 × 12

= 96

`x_4/20 = 8/1`

=> x4 = 8 × 20

= 160

The table can be drawn as follows:

Parts of red pigment 1 4 7 12 20
parts of base 8

32

56 96 160
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Chapter 11: Direct and Inverse Proportions - EXERCISE 11.1 [Page 136]

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NCERT Mathematics [English] Class 8
Chapter 11 Direct and Inverse Proportions
EXERCISE 11.1 | Q 2. | Page 136

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