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The Amount of Extension in an Elastic String Varies Directly as the Weight Hung on It. If a Weight of 150 Gm Produces an Extension of 2.9 Cm, Then What Weight Would Produce an Extension of 17.4 Cm?

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Question

The amount of extension in an elastic string varies directly as the weight hung on it. If a weight of 150 gm produces an extension of 2.9 cm, then what weight would produce an extension of 17.4 cm?

Short/Brief Note
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Solution

Let x gm be the weight that would produce an extension of 17.4 cm.
 

Weight (in gm) 150 x
Length (in cm) 2.9 17.4

\[ \text{ Since the amount of extension in an elastic string and the weight hung on it are in direct variation, we have } : \]
\[\frac{150}{x} = \frac{2 . 9}{17 . 4}\]
\[ \Rightarrow 17 . 4 \times 150 = 2 . 9 \times x\]
\[ \Rightarrow x = \frac{17 . 4 \times 150}{2 . 9}\]
\[ = \frac{2610}{2 . 9}\]
\[ = 900\]
\[\text{ Thus, the required weight will be 900 gm }  .\]

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Chapter 10: Direct and Inverse Variations - Exercise 10.1 [Page 7]

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R.D. Sharma Mathematics [English] Class 8
Chapter 10 Direct and Inverse Variations
Exercise 10.1 | Q 20 | Page 7

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