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A 5 m 60 cm high vertical pole casts a shadow 3 m 20 cm long. Find at the same time the length of the shadow cast by another pole 10 m 50 cm high. - Mathematics

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Question

A 5 m 60 cm high vertical pole casts a shadow 3 m 20 cm long. Find at the same time the length of the shadow cast by another pole 10 m 50 cm high.

Sum
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Solution

Let the length of the shadow of the other pole be x m.

1 m = 100 cm

The given information, in the form of a table, is as follows:

Given, length of shadow of 5 m 60 cm high vertical pole = 3 m 20 cm

We know that 5 m 60 cm = 5 × 100 + 60

= 500 + 60

= 560 cm

3 m 20 cm = 3 × 100 + 20

= 300 + 20

= 320 cm

Length of second pillar = 10 m 50 cm

= 10 × 100 + 50

= 1000 + 50

= 1050 cm

Let the length of the shadow of the pillar = x

ratio of both

Then `560/320 = 1050/x`

on multiplying thunderbolts

560 × x = 1050 × 320

`x = (1050×320)/560`

x = 600

Hence, length of shadow of the pillar = 600 cm = 6 m

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Chapter 13: Direct and Inverse Proportions - Exercise 13.1 [Page 208]

APPEARS IN

NCERT Mathematics [English] Class 8
Chapter 13 Direct and Inverse Proportions
Exercise 13.1 | Q 9.1 | Page 208

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