Question

A 5 m 60 cm high vertical pole casts a shadow 3 m 20 cm long. Find at the same time the length of the shadow cast by another pole 10 m 50 cm high.

Answer 1

Let the length of the shadow of the other pole be x m.

1 m = 100 cm

The given information, in the form of a table, is as follows:

Given, length of shadow of 5 m 60 cm high vertical pole = 3 m 20 cm

We know that 5 m 60 cm = 5 × 100 + 60

= 500 + 60

= 560 cm

3 m 20 cm = 3 × 100 + 20

= 300 + 20

= 320 cm

Length of second pillar = 10 m 50 cm

= 10 × 100 + 50

= 1000 + 50

= 1050 cm

Let the length of the shadow of the pillar = x

ratio of both

Then `560/320 = 1050/x`

on multiplying thunderbolts

560 × x = 1050 × 320

`x = (1050×320)/560`

x = 600

Hence, length of shadow of the pillar = 600 cm = 6 m