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प्रश्न
A mixture of paint is prepared by mixing 1 part of red pigments with 8 parts of base. In the following table, find the parts of the base that need to be added.
| Parts of red pigment | 1 | 4 | 7 | 12 | 20 |
| parts of base | 8 | .... | .... | .... | .... |
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उत्तर
The given mixture of paint is prepared by mixing 1 part of red pigments with 8 parts of base. For more parts of red pigments, the parts of the base will also be more.
Therefore, the parts of red pigments and the parts of the base are in direct proportion. The given information, in the form of a table, is as follows.
According to direct proportion,
`x_1/4 = 8/1`
=> x1 = 4 × 8
= 32
`x_2/7 = 8/1`
=> x2 = 7 × 8
= 56
`x_3/12 = 8/1`
=> x3 = 8 × 12
= 96
`x_4/20 = 8/1`
=> x4 = 8 × 20
= 160
The table can be drawn as follows:
| Parts of red pigment | 1 | 4 | 7 | 12 | 20 |
| parts of base | 8 |
32 |
56 | 96 | 160 |
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