Question

In Question 2 above, if 1 part of a red pigment requires 75 mL of base, how much red pigment should we mix with 1800 mL of base?

Answer 1

Let the parts of red pigment required to mix with 1800 mL of base be x.

The given information, in the form of a table, is as follows:

Parts of red pigment	1	x
Parts of base (in mL)	75	1800

The parts of red pigment and the parts of the base are in direct proportion.

Therefore, we obtain

`1/75 = x/1800`

=> x = `(1 xx 1800)/75`

=> x = 24

Thus, 24 parts of red pigments should be mixed with 1800 mL of base.